Which of the following has a square planar ge | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In $[PtCl_4]^{2-}$,the central metal ion is $Pt^{2 }$ ($5d^8$ configuration).$Pt$ is a $5d$ series element,and for $5d$ elements,the crystal field

Vedclass · Accepted Answer

$[PtCl_4]^{2-}$

Vedclass · Answer

(A) In $[PtCl_4]^{2-}$,the central metal ion is $Pt^{2 }$ ($5d^8$ configuration).$Pt$ is a $5d$ series element,and for $5d$ elements,the crystal field splitting energy $(\Delta_o)$ is very high,even with weak ligands like $Cl^-$.This high splitting energy forces the pairing of electrons in the $5d$ orbitals,resulting in $dsp^2$ hybridization.Therefore,$[PtCl_4]^{2-}$ exhibits a square planar geometry.In contrast,$[NiCl_4]^{2-}$,$[CoCl_4]^{2-}$,and $[FeCl_4]^{2-}$ involve $3d$ metals with weak ligands,leading to $sp^3$ hybridization and tetrahedral geometry.

Which of the following has a square planar geometry?
(At. nos.: $Fe=26, Co=27, Ni=28, Pt=78$)

Similar Questions

Identify,from the following,the diamagnetic,tetrahedral complex.

What type of hybridization is exhibited by $[CoF_6]^{3-}$?

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

In the complex $[SbF_5]^{2-}$,$sp^3d$ hybridization is present. The geometry of the complex is

What is true for $[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following has a square planar geometry?(At. nos.: $Fe=26, Co=27, Ni=28, Pt=78$)